(4x^2+19x+8)/(x+4)

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Solution for (4x^2+19x+8)/(x+4) equation: 


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

(4*x^2+19*x+8)/(x+4) = 0

4*x^2+19*x+8 = 0

4*x^2+19*x+8 = 0

DELTA = 19^2-(4*4*8)

DELTA = 233

DELTA > 0

x = (233^(1/2)-19)/(2*4) or x = (-233^(1/2)-19)/(2*4)

x = (233^(1/2)-19)/8 or x = (-(233^(1/2)+19))/8

(x+(233^(1/2)+19)/8)*(x-((233^(1/2)-19)/8)) = 0

((x+(233^(1/2)+19)/8)*(x-((233^(1/2)-19)/8)))/(x+4) = 0

( x+(233^(1/2)+19)/8 )

x+(233^(1/2)+19)/8 = 0 // - (233^(1/2)+19)/8

x = -((233^(1/2)+19)/8)

( x-((233^(1/2)-19)/8) )

x-((233^(1/2)-19)/8) = 0 // + (233^(1/2)-19)/8

x = (233^(1/2)-19)/8

x in { -((233^(1/2)+19)/8), (233^(1/2)-19)/8 }

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